Description
Questions:
1. Explain the terms Algorithm, Programming, Signed, Unsigned, Variable
– Algorithm: logical way to solve a problem. Steps to get to a solution
– Programming: Using computers to solve problems
– Signed: Includes signing method (can be neg and pos)
– Unsigned: Can only be 0, >0
2. Convert 51BASE10 to BASE2
51BASE10 = 0*2^6 + 1*2^5 + 1*2^4 + 0*2^3 + 0*2^2 + 1*2^1 + 1*2^0 = 110011BASE2
3. Convert unsigned binary 10110011BASE2 to BASE10
1*2^7 + 1*2^5 + 1*2^4 + 1*2^1 + 1*2^0 = 179BASE10
4. Convert signed binary 10110011BASE2 to BASE10
Using Sign Bit: Sign bit (bit 0, first bit, =1=negative) -(0*2^6 + 1*2^5 + 1*2^4 + 0*2^3 + 0*2^2 + 1*2^1 + 1*2^0) = -51BASE10
Using 2’s complement: First bit is negative. [1] flip all: 10110011 –> 01001100 [2] add 1: 01001100 –> 01001101 = (1*2^6 + 1*2^3 + 1*2^2 + 1*2^0) = -77BASE10
5.1. Using a byte of space, what happens when you add 1 to the unsigned binary number 11111111BASE2
11111111BASE2+1 = 00000000BASE2 = 0BASE10 (overflow, rollover)
5.2. What about adding adding 1BASE2 to the signed binary 01111111BASE2
01111111BASE2+1 = 10000000BASE2 = -128BASE10 (overflow,rollover)
6.1. Using a byte of space, what happens when you subtract 1 from the unsigned binary 00000000BASE2 (aka what is BASE2 of -1)
00000000BASE2-1 = 11111111BASE2 (overflow, rollover)
6.2. What about adding 1 to the signed binary 10000000BASE2
10000000BASE2 +1 = 11111111BASE2=-127BASE10
7. Explain and list # of bytes for the following types: int, float, double, char, bool:
– int: Integer. 4 bytes
– float: for smaller floating point numbers (see double). 4 bytes
– double: Double length float. 8 bytes
– char: single character (needs ” not “”). 1 byte
– bool: boolean (T/F aka 1/0). 1 byte
8. Why can int types store chars, and visa-versa
Because chars are stored as their ASCII equicalent (see http://www.asciitable.com/) which is just an integer.
9. Which matters more: variable name or variable type
Variable type. Name is not as crucial.
10. In the following LOC’s (not included) what will be printed
7,7,12,12,19
