Description
For the questions in this part, use the following
lists as needed:
mylist01 = [2,5,4,9,10,-3,5,5,3,-8,0,2,3,8,8,-2,-4,0,6]
mylist02 = [-7,-3,8,-5,-5,-2,4,6,7,5,9,10,2,13,-12,-4,1]
A1. Find the last four digits of the 13th Mersenne
prime, which is equal to 2^521 – 1.
A2. Find the product of the 7th entry in mylist01,
the 13th entry in mylist01, and the 4th entry
in mylist02.
A3. Extract the sublist of mylist02 that goes from
the 5th to the 9th elements (inclusive).
A4. Concatenate mylist01 to mylist02, sort the new
combined list, then extract the sublist that
goes from the 8th to the 19th elements (inclusive).
A5. Determine the number of times 8 appears in the
combined list in A4.
A6. Create a new list be removing all of the 3’s from
mylist01.
A7. Extract a sublist of mylist02 consisting of every
3rd entry, starting at the end and going in
reverse.
A8. From the combined list in A4, extract a sublist of
every 5th entry, starting with the 3rd entry.
%%
Assignment 1, Part B
For the questions in this part, use the following
lists as needed:
mylist01 = [2,5,4,9,10,-3,5,5,3,-8,0,2,3,8,8,-2,-4,0,6]
mylist02 = [-7,-3,8,-5,-5,-2,4,6,7,5,9,10,2,13,-12,-4,1]
B1. Use a for loop to add up the cubes of the entries
of mylist01.
B2. Use a for loop to create mylist03, which has 15
entries, each the product of the corresponding
entry from mylist01 multiplied by the corresponding
entry from mylist02. That is,
mylist03[i] = mylist01[i]*mylist02[i]
for each 0 <= i <= 14.
B3. Use a for loop to compute the mean of the entries
of mylist02. (Hint: len(mylist02) gives the number
of entries in mylist. This is potentially useful.)
%%
Assignment 1, Part C
For the questions in this part, use the following
lists as needed:
mylist01 = [2,5,4,9,10,-3,5,5,3,-8,0,2,3,8,8,-2,-4,0,6]
mylist02 = [-7,-3,8,-5,-5,-2,4,6,7,5,9,10,2,13,-12,-4,1]
mylist03 = [2,-5,6,7,-2,-3,0,3,0,2,8,7,9,2,0,-2,5,5,6]
biglist = mylist01 + mylist02 + mylist03
C1. Use a for loop to determine the number of entries
in “biglist” that are greater than 4.
C2. Use a for loop to determine the number of entries
in “biglist” that are between -1 and 3 (inclusive).
C3. Create a new list called “mylist04” that contains
the elements of biglist that are not divisible by 3.
%%
