Assignment-2 Normalization;Solution

$35.00 $29.00

For each of the following, explain why or why not a relation is in a particular normal form, underline primary keys and indicate which fields are foreign keys and which relation they are keys into. 1.PetStore(storeBranchName, storeAddr, storeManager,(customerName, customerAddr, customerPhone,(petName, petBreed, petSex, price) ) ) FDs storeBranchName → storeAddr, storeManager customerName → customerAddr, customerPhone customerName,…

5/5 – (2 votes)

You’ll get a: zip file solution

 

Description

5/5 – (2 votes)

For each of the following, explain why or why not a relation is in a particular normal form, underline primary keys and indicate which fields are foreign keys and which relation they are keys into.

1.PetStore(storeBranchName, storeAddr, storeManager,(customerName, customerAddr, customerPhone,(petName, petBreed, petSex, price) ) )

FDs

storeBranchName → storeAddr, storeManager customerName → customerAddr, customerPhone customerName, petName → petBreed, petSex customerName,storeBranchName → petName petBreed → price

a. Is this relation in 1NF? If not, why isn’t it? Then put it in 1NF.

b. Is this relation in 2NF? If not, why isn’t it? Then put it in 2NF.

c. Is this relation in 3NF? If not, why isn’t it? Then put it in 3NF.

2.R(A,B,C,D,E)

Fds

A → A,B,C

C → D

A,C→E

a. Is this relation in 1NF? Why or why not? If not, put it into 1NF.

2b. Is it now in 2NF? Why or why not? If not, put it into 2NF.

2c. Is it now in 3NF? Why or why not? If not, put it into 2NF.

Assignment 2 Normalization 1 of 2

3.price(product,sName,uPrice,qty,storeLocation,unitWeight) Fds

product, sname → qty

sName → storeLocation

product → uprice, unitWeight

a. Is this relation in 1NF? If not, why isn’t it? Then put it in 1NF.

b. Is this relation in 2NF? If not, why isn’t it? Then put it in 2NF.

c.Is this relation in 3NF? If not, why isn’t it? Then put it in 3NF.

4.person(personId, name, country,(phone, type))

FDs

personId → name, country, phone

name → country

phone → type

a. Is this relation in 1NF? If not, why isn’t it? Then put it in 1NF.

b. Is this relation in 2NF? If not, why isn’t it? Then put it in 2NF.

c. Is this relation in 3NF? If not, why isn’t it? Then put it in 3NF.

5.carTheft(VID,vehicleType,(ownerID,ownerName), (suspectId,suspectName)) FDs

VID → vehicleType, ownerID

ownerId → ownerName

suspectID → suspectName

a. Is this relation in 1NF? If not, why isn’t it? Then put it in 1NF.

b. Is this relation in 2NF? If not, why isn’t it? Then put it in 2NF.

c. Is this relation in 3NF? If not, why isn’t it? Then put it in 3NF.

Assignment 2 Normalization 2 of 2

Assignment-2 Normalization;Solution
$35.00 $29.00