Description
Question 1. [16 marks]
Given a list L, a contiguous sublist M of L is a sublist of L whose elements occur in immediate succession in L. For instance, [4; 7; 2] is a contiguous sublist of [0; 4; 7; 2; 4] but [4; 7; 2] is not a contiguous sublist of [0; 4; 7; 1; 2; 4].
We consider the problem of computing, for a list of integers L, a contiguous sublist M of L with maximum possible sum.
Algorithm 1 M axSublist(L)
<precondition>: L is a list of integers.
<postcondition>: Return a contiguous sublist of L with maximum possible sum.
Part (1) [5 marks]
Using a divide-and-conquer approach, devise a recursive algorithm which meets the requirements of M axSublist.
Part (2) [8 marks]
Give a complete proof of correctness for your algorithm. If you use an iterative subprocess, prove the correctness of this also.
Part (3) [3 marks]
Analyze the running time of your algorithm.
Question 2. [18 marks]
For a point x 2 Q and a closed interval I = [a; b], a; b 2 Q, we say that I covers x if a x b. Given a set of points S = fx1; : : : ; xng and a set of closed intervals Y = fI1; : : : ; Ikg we say that Y covers S if every point xi in S is covered by some interval Ij in Y .
In the “Interval Point Cover” problem, we are given a set of points S and a set of closed intervals Y . The goal is to produce a minimum-size subset Y ′ Y such that Y ′ covers S.
Consider the following greedy strategy for the problem.
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CSC236: Introduction to the Theory of Computation Due:
Algorithm 2 Cover(S; Y )
<precondition>:
S is a finite collection of points in Q. Y is finite set of closed intervals which covers S.
<postcondition>:
Return a subset Z of Y such that Z is the smallest subset of Y which covers S.
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L = fx1; : : : ; xng S sorted in nondecreasing order
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Z ∅
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i 0
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while i < n do
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if xi+1 is not covered by some interval in Z then
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I interval [a; b] in Y which maximizes b subject to [a; b] containing xi+1
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Z:append(I)
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i i + 1
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return Z
Give a complete proof of correctness for Cover subject to its precondition and postcondition.
Question 3. [10 marks]
The first three parts of this question deals with properties of regular expressions (this is question 4 from section 7.7 of Vassos’ textbook). Two regular expressions R and S are equivalent, written R S if their underlying language is the same i.e. L(R) = L(S). Let R; S, and T be arbitrary regular expression. For each assertion, state whether it is true or false and justify your answer.
Part (1) [2 marks]
If RS SR then R S.
Part (2) [2 marks]
If RS RT and R ̸ ∅then S T .
Part (3) [2 marks]
(RS+R) R R(SR+R) :
Part (4) [4 marks]
Prove or disprove the following statement: for every regular expression R, there exists a FA M such that L(R) = L(M ). Note: even if you find the proof of this somewhere else, please try to write up the proof in your own words. Just citing the proof is NOT enough.
Question 4. [16 marks]
In the following, for each language R and a DFA M such that L(R) =
L over the alphabet = f0; 1g construct a regular expression L(M ) = L. Prove the correctness of your DFA.
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Due: |
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Part (1) |
[8 marks] |
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Let L1 = |
f |
x |
2 f |
0; 1 |
g |
: the first and last charactes of x are the same |
g |
. Note: ϵ = L since ϵ does |
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2 |
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not have a first or last character. |
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Part (2) |
[8 marks] |
Let a block be a maximal sequence of identical characters in a finite string. For example, the string 0010101111 can be broken up into blocks: 00, 1, 0, 1, 0, 1111. Let L2 = fx 2 f0; 1g : x only contains blocks of length at least threeg.
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