Homework 13 Solution

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MATH 141: Linear Analysis I 2 1 0 1 3. Write 1-3 sentences that interpret 1. Find all eigenvectors and eigenvalues of the matrix B = 0 4 0 12 2 2 these geometrically—in other words, what do the eigenvectors and eigenvalues tell you about the trans- 4 5 formation geometrically (in terms of stretch…

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MATH 141: Linear Analysis I

2

1

0

1

3. Write 1-3 sentences that interpret

1. Find all eigenvectors and eigenvalues of the matrix B =

0

4

0

12

2

2

these geometrically—in other words, what do the

eigenvectors and eigenvalues tell you about the trans-

4

5

formation geometrically (in terms of stretch factors and stretch directions)?

  1. Construct an example for each of the following, or explain why such an example does not exist:

    1. a 2 2 matrix that is invertible but not diagonalizable

    1. a 2 2 non-diagonal matrix that is diagonalizable but not invertible

  1. (Strang x5.2 #11) If all eigenvalues of A are 1, 1, and 2, which of the following are certain to be true? Give a reason if true or a counterexample if false.

    1. A is invertible.

    1. A is diagonalizable.

    1. A is not diagonalizable.

2 3

1

4. (Strang x5.2 #12) Suppose the only eigenvectors of A are multiples of ~x = 405, which of the following are

0

certain to be true? Give a reason if true or a counterexample if false.

    1. A is not invertible.

    1. A has a repeated eigenvalue.

    1. A is not diagonalizable.

  1. (Strang x5.1 #18) Suppose a 3 3 matrix A has eigenvalues 0, 3, and 5 with associated eigenvectors ~u, ~v, and w~ respectively.

(a)

Since the eigenvalues of A are all distinct, the set f~u; ~v; w~g is

.

(b)

Write down a basis for the nullspace N(A) and the column space C(A).

(c)

Find one particular solution to A~x = ~v + w~. Find all solutions to A~x = ~v + w~.

(d)

Explain why A~x = ~u does not have a solution. (Hint: If there is a solution, then

is in C(A).

Explain why that is impossible.)

    1. Is A invertible? Why or why not?

  1. Let A be an n-by-n matrix. Suppose A~u = 2~u and A~v = 5~v for nonzero vectors ~u and ~v. Complete the following proof that f~u; ~vg is linearly independent.

Proof: In order for f~u; ~vg to be linearly independent, we need to show that

the only solution to the vector equation

~

is the trivial one.

x~u + y~v = 0

Note that in this equation, ~u and ~v are known vectors, while x and y are unknown scalars. Now assume that x = a and y = b is some solution to the above equation. That is

~

(1)

a~u + b~v = 0:

MATH 141: Linear Analysis I Homework 13

Multiply both sides of equation (1) by matrix A from the left. Show your calculation details to explain why the following has to be true as well

~

(2)

2a~u + 5b~v = 0:

Explain in detail how combing vectors equations (1) and (2) leads to the conclusion that a = 0 = b. There-

fore, the only solution to x~u + y~v = ~0 is the trivial solution.

  1. In one of the reflection questions, you saw that if A is 2 2 matrix then the product of its eigenvalues is equal to det(A) and the sum is equal to trace(A). The following shows that both claims still hold true for n n matrices.

Suppose that 1; 2; : : : ; n are the n eigenvalues of an n n matrix A. i’s are the roots of the polynomial det(A I), which means that we have a factorization

det(A I) = ( 1 )( 2 ) ( n )

(3)

  1. (Strang x5.1 #8) By making a clever choice of the value for in equation (3), show that det(A) is equal to the product of eigenvalues.

  1. (Strang x5.1 #9) Show that trace(A) is equal to the sum of eigenvalues in three steps. First, find the

coefficient of ( )n 1 on the righthand side of equation (3). Next, find all terms on the righthand side

of the following that involves (

)n 1

2

3

a21

a22

a2n

6

a11

a12

a1n

7

det(A

I) = det

...

...

...

;

6

a

a

n2

a

nn

7

6

n1

7

4

5

where aij are the entries of A. Add up all those terms to find the coefficient of (

)n 1.

Lastly,

compare the coefficient of ( )n 1 found in these two different ways.

Homework 13 Solution
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