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(if you have not done this problem from last week) (Strang x2.2 #39) Explain why all these statements are
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all false (all statements are about solving linear systems A~x = b):
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The complete solution is any linear combination of ~xparticular and ~xnullspace.
(b)
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A system A~x = b has at most one particular solution.
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The solution ~xparticular with all free variables zero is the shortest solution (minimum length k~xk). (Find a 2 2 counterexample.)
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If A is invertible there is no solution ~xnullspace in the nullspace. (Lei Yue’s comment: you do not even need to know what it means to say a matrix is invertible.)
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(Making connections of different perspectives of the same idea)
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Write equivalent statements of the sentence:
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A~x = ~0 has only the ~x = ~0 solution.
Explain in each case why your statement is equivalent.
i. in term of N(A) or C(A);
ii. in terms of pivots of A;
iii. in terms of the column vectors of A;
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iv. in terms of the existence and/or uniqueness of solutions to A~x = b for other b’s.
(b) Write equivalent statements of (in other words, necessary and sufficient conditions to) the sentence:
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in term of N(A) or C(A);
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in terms of pivots of A;
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in terms of the column vectors of A;
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Complete the worksheet titled ”Existence and Uniqueness of Solutions”. Study your examples, and sum-marize the method to come up with examples satisfying each pair of criteria twice:
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once in terms of pivots of the matrix A, and
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another time in terms of values of m, n, and r, where m is the number of rows of A, n the number of columns, and r = rank(A). Recall that rank(A) is, by definition, the number of pivots of A.
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Do you think the set of all special solutions to A~x = 0 are linearly dependent, independent. or cannot be |
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decided (meaning that special solutions to certain homogeneous systems are dependent while to others |
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are independent)? Explain your reasoning. |
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3. Determine the following state- |
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A is a 3-by-4 matrix and its upper echelon form is U = |
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ments true or false. Explain your reasoning. |
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The first and third columns of U are linearly independent.
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The second column of U is a linear combination of its first and third columns. So is the fourth column of U.
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of matrix A. Find ker(LA).
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of matrix A. Describe range(LA).
MATH 141: Linear Analysis I Homework 06
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The first and third columns of the original matrix A are linearly independent.
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The second column of the original matrix A is a linear combination of its first and third column. So is the fourth column of A.
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A and U have the same column space. That is, C(A) = C(U).
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6. Let A =
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and denote the function it defines as LA. That is, LA : Rn ! Rm, LA(~x) = A~x.
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Answer the following questions about this particular LA.
(a) What are the values of m and n?
(b) ker(LA) is another name for
(c) range(LA) is another name for
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3
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2
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Find the image under LA of ~u = 4 1 5. Find all vectors ~x’s who have the same LA(~u) as its image. 1
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Let Am n by an m-by-n matrix and LA : Rn ! Rm the function it defines. Complete the following sentences and explain your reasoning.
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(a) LA is onto if and only if range(LA)
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(b) LA is one-to-one if and only if ker(LA)
. Hint: You may find problem#4 of Homework05
helpful.
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For the A and LA from the previous problem, is LA one-to-one? Is LA onto?
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(making connections) Use the previous two problems as hint to write down the more general statements in this problem.
Let A be an m n matrix and define LA : Rn ! Rm by LA(~x) = A~x.
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Write down equivalent statements to
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”LA is one-to-one”
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in terms of the existence and/or uniqueness of solutions;
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in term of nullspace or column space of A;
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in terms of the column vectors of A;
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in terms of pivots in A.
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Write down equivalent statements to
”LA is onto”
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in terms of the existence and/or uniqueness of solutions;
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in term of nullspace or column space of A;
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in terms of the column vectors of A;
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in terms of pivots in A.
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