Description
-
(if you did not finish this last week) T : Rn ! Rm is a linear transformation.
-
-
Is ker(T ) a subspace of Rn?. Explain your reasoning. If yes, how can you find a basis for ker(T )?
-
-
-
Is range(T ) a subspace of Rm?. Explain your reasoning. If yes, how can you find a basis for range(T )?
-
(Hint: Connect ker(T ) and range(T ) to column space and nullspace of some matrix.)
2. A7 5 is matrix with 7 rows and 5 columns. The columns of A satisfy
(column-3) = 5(column-2) + (column-4):
Write down one concrete vector in N(A). Explain your reasoning.
3. In class, we agreed that , the set of all solutions to ~, is a vector subspace. What about all
N(A) A~x = 0
solutions to an inhomogeneous system? More precisely, given a fixed matrix Am n and fixed right hand
-
~
~
m
, define
~
side vector 0
6= b in R
V = fall solutions to A~x = bg:
Is V a vector subspace of Rn?
-
In class, we discussed to think of matrix multiplication as composition of functions. We thought about how, if you have (AB)~x, where A and B are matrices and ~x is a vector, (AB)~x = A(B~x) could be thought of as B transforming ~x first, and then A transforming the result of B~x.
!B! !A!
Bx A(Bx )
x
A(Bx )
Transformed by B first
The result transformed by A
This exercise reinforces that connection.
(a) Given functions f and g below
f(x) = 2x + 4 g(x) = x2 3x
compute
-
-
f(g(x)) and g(f(x))
-
-
-
f(g(2)) and g(f(2))
-
-
Let the matrices F and G be defined as below. Answer the following questions accordingly.
-
F =
22
1
03
G =
20
3
23
4
1
0
2
5
2
4
1
5
0
3
4
45
0
1
-
-
3
-
1
-
Let ~x = 4 2 5, and let G~x = ~y. Compute G~x and compute F ~y. 1
MATH 141: Linear Analysis I Homework 09
-
-
Let ~x be the same vector as in i., and let F ~x = ~u. Compute F ~x and compute G~u.
-
-
-
Compute F G and GF .
-
-
Summarize, in words, the similarities between matrix multiplication and composition of functions. Point out the equivalence, in terms of compositions of functions f and g, of the various quantities in part (b): G~x, F ~y, F ~x, G~u, F G and GF . All notations have the same meaning as in parts (a) and (b).
-
Is matrix multiplication commutative (That is, AB = BA for any matrices A and B)? Why or why not?
When we solved the Italicizing N Task 1 problem in class, some groups have written all the input vectors side by side into a matrix and all the output vectors the same way:
-
0
4=3
3
3
3
=
4
4
4
1
1=3
0
2
0
1
1
1
We used that as an example to introduce one interpretation of matrix multiplication—-each column of the prod-uct matrix AB is the product of matrix A with the corresponding column vector of matrix B. Keep this interpre-tation in mind when answering following questions.
-
In order for us to be able to multiply two matrices A and B together, what conditions do we have to put on the shapes of A and B? What is the shape of the product matrix AB?
-
(a) Fill in the blanks and explain your reasoning: Each column vector of the product matrix AB is
-
a linear combination of
, and so each column vector of AB is in the span of
.
-
-
As a consequence of part (a), what can you say about the relation among three column spaces C(AB), C(A), and C(B)?
-
-
Assume that AB is defined. Determine the following statements true or false. If true, provide a justifica-tion. If false, provide a counterexample.
Hint: You may start by applying the definition of (in)dependence to columns of A or B and then try to multiply the equation by the other matrix.
-
-
If the columns of B are linearly dependent, then so are the columns of AB.
-
-
-
If the columns of A are linearly independent, then so are the columns of AB.
-
-
True of false? If true, explain why. If false, provide a counterexample. A and B are matrices of appropriate shape so that each addition or multiplication is defined.
-
-
If columns 1 and 3 of B are the same, so are columns 1 and 3 of AB.
-
-
-
If AB and BA are defined then A and B are square.
-
-
-
If AB and BA are defined then AB and BA are square.
-
-
-
(AB)2 = A2B2.
-
-
-
(A+B)2 =A2+2AB+B2
-
-
-
If AB = B then A = I.
-
-
(Strang, x1.6, #25) Suppose that A is a 3 3 matrix with (Row-1)+(Row-2)=(Row-3).
-
-
3
-
1
-
Explain why A~x = 405 cannot have a solution.
0
MATH 141: Linear Analysis I |
Homework 09 |
|
|||
~ |
2 |
b1 |
3 |
~ |
|
4 |
b2 |
5 |
|||
(b) Which right-hand sides b = |
might allow a solution to A~x = b? |
||||
b3 |
-
-
What happens to Row-3 if we perform forward elimination on A?
-
-
-
Explain why each of the above three situations leads to the conclusion that A is not invertible? (Hint: Think in terms of the linear transformation LA that A defines.)
-
-
(Strang, x1.6, #40) True or False. If true, explain why. If false, show a concrete counterexample. (Hint: Use the fact that A is invertible if and only if the linear transformation LA which it defines is invertible.)
-
-
A 4 4 matrix with a row of zeros is not invertible.
-
-
-
A matrix with 1’s down the main diagonal is invertible.
-
-
-
If A is invertible, then A 1 is invertible.
-