Homework 12 Solution

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1. A linear transformation T : R3 ! R3 has an eigenvector 4 0 5 associated with eigenvalue 1=4 and two 2 2 3 2 3 1 eigenvectors 4 15 and 4 15 both associated with eigenvalue 3. Answer all of the following questions 9 without finding the matrix for T . Identify the image…

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1. A linear transformation T : R3 ! R3 has an eigenvector 4 0 5 associated with eigenvalue 1=4 and two

2

2 3 2 3

  • 1

eigenvectors 4 15 and 4 15 both associated with eigenvalue 3. Answer all of the following questions

    • 9

without finding the matrix for T .

  1. Identify the image of following vectors under the transformation T . Be sure to justify your conclu-sions.

2 3 2 3

  • 1=2

(i) 4 0 5 (ii) 4 1=25

  • 9=2

(b) Explain why T

02

35

31

=

3

2

35

3

.

@4

37

5A

4

37

5

      1. 31

1

    1. Calculate T @4 25A. 12

  1. Let T : R2 ! R2 be the linear transformation that reflects the entire R2 across the x-axis.

    1. Without calculating a matrix A for the transformation T , determine what the eigenvectors and eigen-values would be, if any. In other words, does the transformation have any stretch directions and associated stretch factors? Justify your answer.

    1. Find a matrix A to represent the transformation T . Calculate its eigenvectors and associated eigen-values for the matrix A, and verify your answers to part (a).

  • 3

1 1 1

3. Let A = 41

1

1

5.

1

1

1

    1. (Strang x5.2 #3) Without solving det(A I) = 0, use observation to find all eigenvalues of A and then find associated eigenvectors.

Hint 1. What can you say about the rank of A and what does that tell you about the nullspace? What does nullspace have to do with eigen-theory?

Hint 2. Note that the rows of A add up to the same number 3, which would lead you to another eigenvector-eigenvalue pair.

    1. Compute A100 by diagonalizing A.

  1. A is an n n matrix.

    1. (Strang x5.1 #23) Fill in the blanks.

i.

If you know ~x is an eigenvector of A, the way to find the associated eigenvalue is to

.

ii.

f you know is an eigenvalue of A, the way to find an associated eigenvector is to

.

  1. (Strang x5.1 #24) Let be an eigenvalue of A with associated eigenvecter ~x. That is, A~x = ~x. Use part

    1. as a hint to prove the following statements.

      1. 2 is an eigenvalue of A2. (Also review problem #6 of Homework 11.)

      2. If A is invertible, 1 is an eigenvalue of A 1.

      3. + 1 is an eigenvalue of A + I.

Homework 12 Solution
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