Description
1. Show that
-
x =
1
cos x
(1)
2
has a solution in [0; 0:5].
Hint: use the Brouwer’s xed point theorem to show that y = 12 cos x has a xed point in [0; 0:5].
2. This problem is a writing project from Calculus II. The goal is to show that the iteration
1
xn+1 = 2 cos(xn)
will converge to the real solution thus can be used as a numerical algorithm to solve (1). This problem also captures the idea of the proof of the Brouwer’s xed point theorem in general.
Construct the following sequence
1
xn+1 = 2 cos xn; a1 = 0:5 for n = 1; 2; 3; : : :
(a) Show that if the sequence xn converges, the limit x = lim xn will be the solution of (1).
n!1
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Now we only need to show that sequence xn converges. Below are the step by step instructions. Warp them up and write a complete proof. Make you proof precise and good looking with all necessary details included.
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A function f(x) is called a CONTRACTION if there is a positive constant C < 1 such that
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jf(a) f(b)j Cja bj for any a; b in R:
Use the Mean Value Theorem to show that f(x) = 12 cos x is a contraction with C = 1=2. ii. De ne a series yn = xn+1 xn. Use i to show that
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jynj
1
n
1
jy1j
for any positive integer n 2:
2
1
1
n
1
1
X
X
iii. Show that n=1
jy1j is convergent. Then by the comparison test n=1 jynj is convergent.
2
1
X
iv. Use iii to show that
yn is convergent.
n=1
v. The conclusion in iv implies that
lim (an
1) is convergent. Therefore lim an is convergent.
n!1
n!1
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(Challenge) Based on problem 2 prove the following variation of the xed point theorem.
Fixed theorem: let f(x) : [a; b] ! [a; b]. Suppose there is a constant C < 1 such that jf0(x)j C, for any x in [a; b]. Then
1
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f(x) has exactly one xed point x in [a; b]
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Using any x0 in [a; b], the scheme xn+1 = f(xn) converges to x at least linearly.
4. Consider solving f(x) = x3 + 6x2 8 = 0
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Use the Intermediate Value Theorem to show f has a root on [1; 2].
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Consider the xed point iteration de ned by
i. Function g1(x) = x3 + 6x2 + x 8
r
8
ii. Function g2(x) =
x + 6
r
-
x3
iii. Function g3(x) =
6
For each scheme, show that if it converges, it will converge to the zero of f.
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Try each scheme with several random initial x0 in Matlab. What do you see?
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Use the theorem in problem 3 to explain what you saw in (c).
5. Fixed point iteration: Consider the iteration xn = |
1 |
xn |
1 + |
c |
for constant c > 0. |
2 |
xn 1 |
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Prove this iteration converges at least quadratically.
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What will the iteration converge to? Explain.
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Verify your results of parts (a) and (b) in Matlab.
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Relate this iteration to Newton’s Method.
6. Find a solution p to x4 + 2x2 x 3 = 0 using the following methods. |
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A xed point iteration for g1 |
(x) = (3 + x 2x2)1=4 with initial guess x0 |
= 0:5. |
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A xed point iteration for g2 |
3x4 + 2x2 + 3 |
|||
(x) = |
with a initial guess x0 |
= 0:5. |
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4x3 + 4x 1 |
The Secant Method with initial guesses x0 = 0:5; x1 = 2.
Newton’s Method with initial guess x0 = 0:5.
For each, compute until you reach absolute error less than 10 14.
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For each method, print the approximation, absolute error, and computed rate of convergence. Use a table format and label the columns.
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How many steps did each method take to reach the required accuracy?
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For each method, how does the convergence rate compare to the number of correct digits gained at each step?
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(Challenge) Prove the rate of convergence for scheme de ned by g1(x) and g2(x). Use it to support your computed rate of convergence.
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Read the rst two part of the article at http://en.wikipedia.org/wiki/Fixed_point_(mathematics) (everything up to but not including Applications). Wrap up the idea of using xed point theorem to solve equations.
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Write a step by step instruction.
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Give three distinct examples that works ne.
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Give three distinct examples that will fail.
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2