Description
Question 2:
[2] Completely parenthesize the expression below according to the operator table from Question 1.
(((1 + 2) – 3) < (4 * (5 ^ 6)))
[4] Draw the parse tree for this expression according to your expr rule from Question 1. You may omit whitespace from your parse tree.
|- int_val – $
Expr – eq_less – “<”
|- int_val – %
|- mult – expo – atom – int_val – “3”
|
% – Expr – add_sub – “-“ |- mult – expo – atom – int_val – “2”
|- expr – add_sub – “+”
|- mult – expo – atom – int_val – “1”
|- atom – int_val – “6”
|- expo – “^”
$ – Expr – mult – “*” |- atom – int_val – “5”
|
|- expo – atom – int_val – “4”
Question 3
[6] Describe an operator that could be added to the expression language in question 1.
The operand I would add would be the greater than symbol.
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Symbol: “>”
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Arity: binary
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Precedence: at the bottom with “<”
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Associativity: Non-associative
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Type: Integer
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Semantics: Would return a Boolean value of 1 if the left operand is less than the right operand. Otherwise, return a Boolean value of 0.
[2] Explain the approach you would take to add this operator to your grammar.
To implement this, I would change my ‘eq_less’ nonterminal to be named ‘eq_less_greater’ and implement the functionality therein. There would also need to be a new terminal to recognize the symbol that would then be appropriately implemented in our renamed function.
