Systems and Networks Homework 2 Solution

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Problem 1: Getting Started with the RAMA-2200 In this homework, you will be using the RAMA-2200 ISA to complete a Fibonacci function. Before you begin, you should familiarize yourself with the available instructions, the register conventions and the calling convention of RAMA-2200. Details can be found in the section, Appendix A: RAMA-2200 Instruction Set Architecture,…

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  • Problem 1: Getting Started with the RAMA-2200

In this homework, you will be using the RAMA-2200 ISA to complete a Fibonacci function. Before you begin, you should familiarize yourself with the available instructions, the register conventions and the calling convention of RAMA-2200. Details can be found in the section, Appendix A: RAMA-2200 Instruction Set Architecture, at the end of this document.

The assembly folder contains several tools for you to use:

assembler.py: a basic assembler that can take your assembly code and convert it into binary instruc-tions for the RAMA-2200.

rama2200.py: the ISA de nition le for the assembler, which tells assembler.py the instructions sup-ported by the RAMA-2200 and their formats.

rama2200-sim.py: A simulator of the RAMA-2200 machine. The simulator reads binary instructions and emulates the RAMA-2200 machine, letting you single-step through instructions and check their results.

To learn how to run these tools, see the README.md le in the assembly directory.

Before you begin work on the second problem of the homework, try writing a simple program for the RAMA-2200 architecture. This should help you familiarize yourself with the available instructions.

We have provided a template, mod.s, for you to use for this purpose. Try writing a program that performs the mod operation on the two provided arguments. A correct implementation will result in a value of 2.

You can use the following C code snippet as a guide to implement this function:

int mod ( int a , int b ) {

int x = a ;

while ( x >= b ) {

x = x – b ;

}

return x ;

}

There is no turn-in for this portion of the assignment, but it is recommended that you attempt it in order to familiarize yourself with the ISA.

Homework 2 CS 2200 – Systems and Networks Fall 2019

  • Problem 2: Fibonacci Number

For this problem, you will be implementing the missing portions of the Fibonacci Number program we have provided for you.

You’ll be nishing a recursive implementation of the Fibonacci Number program that follows the RAMA-2200 calling convention. Recursive functions always obtain a return address through the function call and return to the callee using the return address.

You must use the stack pointer ($sp) and frame pointer ($fp) registers as described in the textbook and lecture slides.

Here is the C code for the Fibonacci Number algorithm you have been provided:

int fib ( int n ) {

if ( n <= 1) {

if ( n < 0) {

n = 0;

}

return n ;

}

else {

return fib (n -1) + fib (n -2) ;

}

}

Note that this C code is just to help your understanding and does not need to be exactly followed. However, your assembly code implementation should meet all of the given conditions in the description.

Open the fib.s le in the assembly directory. This le contains an implementation of the Fibonacci Number program that is missing signi cant portions of the calling convention.

Complete the given Fibonacci number subroutine by implementing the various missing portions of the RAMA-2200 calling convention. Each location where you need to implement a portion of the calling con-vention is marked with a TODO label as well as a short hint describing the portion of the calling convention you should be implementing.

There are some important restrictions / reminders for this assignment.

  1. Store parameters to s registers during setup stage of RAMA-2200 calling convention (there will be an instruction in the code).

  1. Do NOT use stack to store local variables.

Please note that we will be testing your implementation for multiple values of n, so please do not attempt to hardcode your solutions. We will be testing for all possible values of n, where n is an integer.

  • Problem 3: Short Answer

Please answer the following question in the le named answers.txt:

  1. The RAMA-2200 instruction set contains an instruction called goto that is used to go to a certain location within the code, speci ed by a label. However, this functionality could be emulated using a combination of other instructions available in the ISA. Describe a sequence of other instructions in the RAMA-2200 ISA that you may use to accomplish the functionality of goto.

Homework 2 CS 2200 – Systems and Networks Fall 2019

  • Deliverables

fib.s: your assembly code from Section 2

answers.txt: your answer to the problem from Section 3 Submit these les to Canvas before the assignment deadline.

The TAs should be able to type python assembler.py -i rama2200 –sym fib.s and then python rama2200-sim.py fib.bin to run your code. If you cannot do this with your submission, then you have done something wrong.

Homework 2 CS 2200 – Systems and Networks Fall 2019

  • Appendix A: RAMA-2200 Instruction Set Architecture

The RAMA-2200 is a simple, yet capable computer architecture. The RAMA-2200 combines attributes of both ARM and the LC-2200 ISA de ned in the Ramachandran & Leahy textbook for CS 2200.

The RAMA-2200 is a word-addressable, 32-bit computer. All addresses refer to words, i.e. the rst word (four bytes) in memory occupies address 0x0, the second word, 0x1, etc.

All memory addresses are truncated to 16 bits on access, discarding the 16 most signi cant bits if the address was stored in a 32-bit register. This provides roughly 64 KB of addressable memory.

5.1 Registers

The RAMA-2200 has 16 general-purpose registers. While there are no hardware-enforced restraints on the uses of these registers, your code is expected to follow the conventions outlined below.

Table 1: Registers and their Uses

Register Number

Name

Use

Callee Save?

0

$zero

Always Zero

NA

1

$at

Assembler/Target Address

NA

2

$v0

Return Value

No

3

$a0

Argument 1

No

4

$a1

Argument 2

No

5

$a2

Argument 3

No

6

$t0

Temporary Variable

No

7

$t1

Temporary Variable

No

8

$t2

Temporary Variable

No

9

$s0

Saved Register

Yes

10

$s1

Saved Register

Yes

11

$s2

Saved Register

Yes

12

$k0

Reserved for OS and Traps

NA

13

$sp

Stack Pointer

No

14

$fp

Frame Pointer

Yes

15

$ra

Return Address

No

  1. Register 0 is always read as zero. Any values written to it are discarded. Note: for the purposes of this project, you must implement the zero register. Regardless of what is written to this register, it should always output zero.

  1. Register 1 is used to hold the target address of a jump. It may also be used by pseudo-instructions generated by the assembler.

  1. Register 2 is where you should store any returned value from a subroutine call.

  1. Registers 3 – 5 are used to store function/subroutine arguments. Note: registers 2 through 8 should be placed on the stack if the caller wants to retain those values. These registers are fair game for the callee (subroutine) to trash.

  1. Registers 6 – 8 are designated for temporary variables. The caller must save these registers if they want these values to be retained.

  1. Registers 9 – 11 are saved registers. The caller may assume that these registers are never tampered with by the subroutine. If the subroutine needs these registers, then it should place them on the stack and restore them before they jump back to the caller.

Homework 2 CS 2200 – Systems and Networks Fall 2019

  1. Register 12 is reserved for handling interrupts. While it should be implemented, it otherwise will not have any special use on this assignment.

  1. Register 13 is your anchor on the stack. It keeps track of the top of the activation record for a subroutine.

  1. Register 14 is used to point to the rst address on the activation record for the currently executing process.

  1. Register 15 is used to store the address a subroutine should return to when it is nished executing.

5.2 Instruction Overview

The RAMA-2200 supports a variety of instruction forms, only a few of which we will use for this project.

The instructions we will implement in this project are summarized below.

Table 2: RAMA-2200 Instruction Set

31302928272625242322212019181716151413121110 9 8 7 6 5 4 3 2 1 0

ADD

0000

DR

SR1

unused

SR2

NAND

0001

DR

SR1

unused

SR2

ADDI

0010

DR

SR1

immval20

LW

0011

DR

BaseR

o set20

SW

0100

SR

BaseR

o set20

GOTO

0101

0000

unused

PCo set20

JALR

0110

RA

AT

unused

HALT

0111

unused

SKP

1000

mode

SR1

unused

SR2

LEA

1001

DR

unused

PCo set20

5.2.1 Conditional Branching

Conditional branching in the RAMA-2200 ISA is provided via two instructions: the SKP (\skip”) instruction and the GOTO (\unconditional branch”) instruction. The SKP instruction compares two registers and skips the immediately following instruction if the comparison evaluates to true. If the action to be conditionally executed is only a single instruction, it can be placed immediately following the SKP instruction. Otherwise a GOTO can be placed following the SKP instruction to branch over to a longer sequence of instructions to be conditionally executed.

Homework 2 CS 2200 – Systems and Networks Fall 2019

5.3 Detailed Instruction Reference

5.3.1 ADD

Assembler Syntax

ADD DR, SR1, SR2

Encoding

31302928272625242322212019181716151413121110 9 8 7 6 5 4 3 2 1 0

Homework 2

CS 2200 – Systems and Networks

Fall 2019

5.3.3

ADDI

Assembler Syntax

ADDI

DR, SR1, immval20

Encoding

31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10

9

8

7

6

5

4

3

2

1

0

Homework 2 CS 2200 – Systems and Networks Fall 2019

5.3.7 JALR

Assembler Syntax

JALR RA, AT

Encoding

31302928272625242322212019181716151413121110 9 8 7 6 5 4 3 2 1 0

Homework 2 CS 2200 – Systems and Networks Fall 2019

5.3.9 SKP

Assembler Syntax

SKPE SR1, SR2

SKPLT SR1, SR2

Encoding

31302928272625242322212019181716151413121110 9 8 7 6 5 4 3 2 1 0

Operation

DR = PC + SEXT(PCoffset20);

Description

An address is computed by sign-extending bits [19:0] to 32 bits and adding this result to the incremented PC (address of instruction + 1). It then stores the computed address into register DR.

Systems and Networks Homework 2 Solution
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