Description
1. REQURIEMENT:
To develop a boot program for booting the MTX operating system.
2. Background Reading List
Notes 2: Booting
3-1. Download the MTX image file
http://www.eecs.wsu.edu/~cs460/samples/LAB1/mtximage
Use it as VIRTUAL FD, as in
qemu-system-i386 -fda mtximage -no-fd-bootchk
Then, boot up MTX from the virtual FD.
Test run the MTX operating system as demonstrated in class.
CONTENTS of the MTX disk image:
| B0 | B1 ……………………………………………… B1339 |
————————————————————————–
|booter| An EXT2 file system for MTX; kernel=/boot/mtx |
————————————————————————–
LAB 1 IS FOR YOU TO WRITE A BOOTER PROGRAM TO REPLACE THE booter IN BLOCK 0
TO BOOT UP THE MTX KERNEL, which is the image file /boot/mtx.
3-2. Background: Computer Architecture and Programming Environment
Lab 1 assumes the following hardware and software environments.
Hardware: Intel X86 based PC running Linux. For convenience, use a virtual
machine that emulates the PC hardware: QEMU, VMware, VirtualBox,
etc.
Software: BCC compiler-assembler-linker under Linux.
When a PC starts, it is in the so-called 16-bit UNPROTECTED mode, also
known as the 16-bit real mode. While in this mode, the PC’s CPU can only
execute 16-bit code and access 1MB memory. The diagram below shows the 1MB
memory layout, shown in 64KB segments.
1MB MEMORY layout in 64KB SEGMENTS
0x0000 0x1000 ……. 0x9000 0xA000 … 0xF000
———————————————————–
| | ………. | | BIOS |
———————————————————–
|<————– 640KB RAM area ———>|<— ROM —–>|
The CPU’s internal registers are
segment registers: CS, DS, SS, ES
general registers: AX, BX, CX, DX, BP, SI, DI
status register : FLAG
stack pointer : SP
instruction point or program counter: IP
All registers are 16-bit wide.
The CPU operates as follows:
1. In real-mode, the CPU has 20-bit address lines for 2**20 = 1MB memory, e.g.
20-bit addresses
0x00000, 0x00010, 0x00020
0x10000, 0x20000, 0x30000, etc.
A segment is a block of memory beginning from a 16-byte boundary. Since the
last 4 bits of a segment address are always 0, it suffices to represent a
segment address by the leading 16 bits. Each segment size is up to 64KB.
2. The CPU in has 4 segment registers, each 16-bits.
CS -> Code segment = program code or instructions
DS -> Data segment = static and global data (ONE COPY only)
SS -> Stack segment = stack area for calling and local variables.
ES -> Extra segment = temp area; may be used for malloc()/mfree()
3. In a program, every address is a 16-bit VIRTUAL address (VA). For each 16-bit
VA, the CPU automatically translates it into a 20-bit PHYSICAL address (PA)
by
(20-bit)PA = ((16-bit)segmentRegister << 4) + (16-bit)VA.
where segmentRegister is either by default or by a segment prefix in the
instruction.
Examples:
Assume CS=0x1234. IP=0x2345 ==> PA = (0x1234<<4) + 0x2345 = 0x14685 (20 bits)
DS=0x1000. mov ax,0x1234 ==> PA=0x10000 + 0x1234 = 0x11234, etc.
IMPORTANT: In a program, every address is a 16-bit VA, which is an OFFSET in a
memory segment. When accessing memory, the CPU maps every VA to a
20-bit PA.
4. The number of DISTINCT segments available to the CPU depends on the
memory model of the executing program, which is determined by the compiler
and linker used to generate the binary executable image. The most often used
memory models are
One-segment model :(COM files): CS=DS=SS all in ONE segment <= 64KB
Separate I&D model:(EXE files): CS=CodeSegment, DS=SS=Data+Stack segment
One-segment model programs can be loaded to, and executed from, any available
segment in memory. In order to run a One-segment memory model program, the
following steps are needed:
(1). A C compiler and assembler which generate 16-bit (object) code
(2). A linker that combines the object code to generate a ONE-segment
binary executable image. We shall use BCC under Linux to do (1) and (2).
(3). LOAD the binary executable image into memory (at a segment boundary)
and set CPU’s CS=DS=SS = loaded segment.
Set SP at the HIGH end of the segment.
Set IP at the beginning instruction in the segment.
Then let the CPU execute the image.
5. PRE-WORK 1: DUE: in one week
5.1. Download files from samples/LAB1/LAB1.1/
Given: The following bs.s file in BCC’s assembly
!==================== bs.s file ===================================
.globl _main ! IMPORT symbols from C code
.globl _getc,_putc ! EXPORT symbols to C code
!——————————————————————–
! Only one SECTOR loaded at (0000,7C00). Load entire block to 0x90000
!——————————————————————–
mov ax, 0x9000 ! set ES to 0x9000
mov es,ax
xor bx,bx ! clear BX = 0
!——————————————————————–
! Call BIOS INT-13 to read BOOT BLOCK to (segment,offset)=(0x9000,0)
!——————————————————————–
xor dx,dx ! DH=head=0, DL=drive=0
xor cx,cx ! CL=cylinder, CL=sector
incb cl ! BIOS counts sector from 1
mov ax, 0x0202 ! AH=READ AL=2 sectors
int 0x13 ! call BIOS INT-13
jmpi start,0x9000 ! CS=0x9000, IP=start
start:
mov ax,cs ! Set segment registers for CPU
mov ds,ax ! we know ES,CS=0x9000. Let DS=CS
mov ss,ax ! SS = CS ===> all point at 0x9000
mov es,ax
mov sp, 8192 ! SP = 8192 above SS=0x9000
!————— OPTIONAL ————————————–
mov ax, 0x0012 ! Call BIOS for 640×480 color mode
int 0x10 !
!————————————————————–
call _main ! call main() in C
jmpi 0,0×1000
!======================== I/O functions =================================
!———————————————
! char getc() function: returns a char
!———————————————
_getc:
xorb ah,ah ! clear ah
int 0x16 ! call BIOS to get a char in AX
ret
!———————————————-
! void putc(char c) function: print a char
!———————————————-
_putc:
push bp
mov bp,sp
movb al,4[bp] ! get the char into aL
movb ah, 14 ! aH = 14
movb bl, 0x0D ! bL = color
int 0x10 ! call BIOS to display the char
pop bp
ret
Write YOUR own t.c file in C:
/************** t.c file **************************/
int prints(char *s)
{
call putc(c) to print string s;
}
int gets(char s[ ])
{
call getc() to input a string into s[ ]
}
main()
{
char name[64];
while(1){
prints(“What’s your name? “);
gets(name);
if (name[0]==0)
break;
prints(“Welcome “); prints(name); prints(“\n\r”);
}
prints(“return to assembly and hang\n\r”);
}
5-3. Use BCC to generate a one-segment binary executable a.out WITHOUT header
as86 -o bs.o bs.s
bcc -c -ansi t.c
ld86 -d bs.o t.o /usr/lib/bcc/libc.a
5-4. dump a.out to a VIRTUAL FD disk:
dd if=a.out of=mtximage bs=1024 count=1 conv=notrunc
5-5. Boot up QEMU from the virtual FD disk:
qemu-system-i386 -fda mtximage -no-fd-bootchk
5-6. For YOUR benefit: do ALL steps of 5-3 to 5-5 by a sh script.
6. PRE-WORK 2: DUE: in ONE week
Download files from samples/LAB1/LAB1.2
mtximage contains an EXT2 file system, block size = 1KB (1024 bytes)
| B0 | B1 B2………………… ………………… B1339 |
————————————————————————–
|booter| SUPER|GD |Bmap|Imap|INODES | |
————————————————————————–
Write your C code to print all the file names in the root directory /
The complete bs.s file:
==========================================================================
BOOTSEG = 0x9000 ! Boot block is loaded again to here.
SSP = 8192 ! Stack pointer at SS+8KB
.globl _main,_prints ! IMPORT symbols
.globl _getc,_putc ! EXPORT symbols
.globl _readfd,_setes,_inces,_error
!——————————————————-
! Only one SECTOR loaded at (0000,7C00). Get entire BLOCK in
!——————————————————-
mov ax, BOOTSEG ! set ES to 0x9000
mov es,ax
xor bx,bx ! clear BX = 0
!—————————————————
! call BIOS to read boot BLOCK to [0x9000,0]
!—————————————————
xor dx,dx ! drive 0, head 0
xor cx,cx
incb cl ! cyl 0, sector 1
mov ax, 0x0202 ! READ 1 block
int 0x13
jmpi start,BOOTSEG ! CS=BOOTSEG, IP=start
start:
mov ax,cs ! Set segment registers for CPU
mov ds,ax ! we know ES,CS=0x9000. Let DS=CS
mov ss,ax ! SS = CS ===> all point at 0x9000
mov es,ax
mov sp, SSP ! SP = 8KB above SS=0x9000
mov ax, 0x0012 ! 640×480 color
int 0x10
call _main ! call main() in C
test ax,ax ! main() return 1 for OK, 0 for BAD
je _error ! if main() return 0, jump to _error
jmpi 0,0×1000
!======================== I/O functions =================================
!———————————————
! char getc() function: returns a char
!———————————————
_getc:
xorb ah,ah ! clear ah
int 0x16 ! call BIOS to get a char in AX
ret
!———————————————-
! void putc(char c) function: print a char
!———————————————-
_putc:
push bp
mov bp,sp
movb al,4[bp] ! get the char into aL
movb ah, 14 ! aH = 14
movb bl, 0x0D ! bL = cyan color
int 0x10 ! call BIOS to display the char
pop bp
ret
!—————————————
! readfd(cyl, head, sector, buf)
! 4 6 8 10 byte offset from stack frame pointer bp
!—————————————
_readfd:
push bp
mov bp,sp ! bp = stack frame pointer
movb dl, 0x00 ! drive in DL: 0=FD0
movb dh, 6[bp] ! head in DH
movb cl, 8[bp] ! sector in CL
incb cl ! BIOS count sector from 1
movb ch, 4[bp] ! cyl in CH
mov bx, 10[bp] ! BX=buf ==> loading memory addr=(ES,BX)
mov ax, 0x0202 ! AH=READ, AL=2 sectors to (EX, BX)
int 0x13 ! call BIOS 0x13 to read the block
jb _error ! to error if CarryBit is on [read failed]
pop bp
ret
_setes: push bp
mov bp,sp
mov ax,4[bp]
mov es,ax
pop bp
ret
_inces: ! inces() inc ES segment by 0x40, or 1KB
mov ax,es
add ax, 0x40
mov es,ax
ret
!——————————
! error & reboot
!——————————
_error:
mov bx, bad
push bx
call _prints
int 0x19 ! reboot
bad: .asciz “Error!”
==================================================================
The getblk(u16 blk, char *buf) function:
int getblk(u16 blk, char *buf)
{
readfd( (2*blk)/CYL, ( (2*blk)%CYL)/TRK, ((2*blk)%CYL)%TRK, buf);
}
The booter runs in the segment 0x9000.
CS, DS, SS, ES are all pointing at the same segment 0x9000.
BIOS will load the disk block blk to (ES, buf), which is the char buf[ ] in
the program.
=========================================================================
7. Modify YOUR t.c in LAB1.2 to get the INODE of /boot/mtx, i.e.
let INODE *ip -> INODE of /boot/mtx
ip->i_blokc[0] to ip->i_block[11] are DIRECT blocks
ip->i_block[12] = IDIRECT block = an array of 32-bit integers, 0 if no more.
To load the blocks into memory starting from (segment) 0x1000
setes(0x1000); // ES = 0x1000 => BIOS loads disk block to (ES, buf)
loop:
getblk((u16)blkno, 0); // buf = 0 => memory address = (ES, 0)
inces(); // inc ES by 1KB/16 = 0x40
repeat loop for next blkno until no more
8. LAB1 main work: DUE: in 2 weeks
Modify t.c file to boot up /boot/mtx from the mtximage VIRTUAL disk
sample solution: mtximage (run qemu on it)
