Problem Set 4 Solution

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Total 100 points. Problem 1. (5 points) Let x be a real number and n an integer. Show that rxs n if and only if x ¤ n x 1: [Hint: Use the de nition for rxs n given as the second fact among the four facts in slide #39 in the lecture slides on…

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Total 100 points.

Problem 1. (5 points) Let x be a real number and n an integer. Show that

rxs n if and only if x ¤ n x 1:

[Hint: Use the de nition for rxs n given as the second fact among the four facts in slide #39 in the lecture slides on Sets and Functions. What you are proving here is the last fact in the same slide.]

Problem 2. (15 points) Let n be a positive integer. Show that if n is a perfect square, then

Problem 3. (10 points) Let f1; f2; f3 be functions from the set N of natural numbers to the set R of real numbers. Suppose that f1 Opf2q and f2 Opf3q. Is it possible that

Problem 4. (10 pts 3 = 30 points) Determine whether each of the following statements is true or false. In each case, answer true or false, and justify your answer (by giving a direct proof if it is true, or a proof by contradiction if it is false; always use the de nition involving the absolute values, as given in class).

Problem 5. (10 points) Let k be a xed positive integer. Show that

1k 2k nk Opnk 1q

holds.

Problem 7. (5 pts 3 = 15 points) Suppose that you have two algorithms A and B that solve the same problem. Algorithm A has worst case running time TApnq 2n2 2n 1 and Algorithm B has worst case running time TBpnq n2 n 1.

  1. Show that both TApnq and TBpnq are in Opn2q.

  2. Show that TApnq 2n2 Opnq and TBpnq n2 Opnq.

    1. Explain which algorithm is preferable.

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Problem Set 4 Solution
$30.00 $24.00