Assignment 3 (Solved)

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Suppose you have the following structure to represent a binary tree: struct Node { int data; Node *left, *right; Node &operator=(const Node &other); }; Without using copy-and-swap, and without modifying the Node structure, give an imple-mentation of Node::operator= that o ers the strong guarantee. Your submission should consist of the le Node.cc that contains the…

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  1. Suppose you have the following structure to represent a binary tree:

struct Node {

int data;

Node *left, *right;

Node &operator=(const Node &other);

};

Without using copy-and-swap, and without modifying the Node structure, give an imple-mentation of Node::operator= that o ers the strong guarantee. Your submission should consist of the le Node.cc that contains the implementation of this one method, along with any auxiliary de nitions and includes that you might need. This problem will be primarily hand-marked.

No test suite required; submit your solution on Due Date 1.

  1. In this problem and the next four, we will revisit the egrep tool that you wrote as part of A1. The scope of that problem was limited, in that we permitted at most one regular expression operator in the search pattern. We now aim to solve the general problem.

When it comes to processing general regular expressions, one of the rst questions we must confront is that of precedence: does c*d|a mean c*(d|a) or (c*d)|a? We will assign the highest precedence to *, then concatenation, then |. For example, in the case of concatenation over |, we would interpret the regular expression (a|b)(c|d)|e as meaning ((a|b)(c|d))|e.

We can express these precedence relationships in the form of a \data de nition” for regular expressions. A regular expression is:

    • a disjunction of two regular expressions, or a regular expression without disjunctions;

where a regular expression without disjunctions is a concatenation of two regular ex-pressions without disjunctions, or a regular expression without disjunctions or concate-

    • nations;

where a regular expression without disjunctions or concatenations is a star operator applied to a regular expression without disjunctions or concatenations, or a regular

    • expression without disjunctions, concatenations, or stars;

where a regular expression withoud disjunctions, concatenations, or stars is a single word (which may be empty), or a pair of parentheses surrounding a regular expression.

The above description is what is known as a concrete syntax: it leaves no question about the precedence of operators, and leaves only one way for a given regular expression to satisfy the de nition (modulo associativity of the disjunction and concatenation operators).

But if already know how the operators of a given regular expression are to be grouped, we may use a much simpler abstract syntax | a regular expression is:

a disjunction of two regular expressions;

or a concatenation of two regular expressions;

  • or a star operator applied to a regular expression; or a single word.

For this problem, you are to create classes corresponding to these four types of regular ex-pression: Disjunction, Concatenation, Star, Word; with an abstract RegExp superclass from which they may inherit. For example, the regular expression (cat|dog)*bird could be encoded as

new Concatenation{

new Star{

new Disjunction{

new Word{“cat”},

new Word {“dog”}

}

},

new Word{“bird”}

};

Your classes must provide a virtual method called matches that takes a string and answers true if the string exactly satis es the regular expression (i.e., with no characters left over), and false otherwise. You may assume that the word in the Word class contains no special characters, or rather, if it does, that those characters should be taken literally.

We will provide a sample main program that contains this example, but you must augment this with your own testing. As always, expect your solutions to be hand-marked.

The les you submit will at least contain the le re.h. That is the le that our testing will include. You may use this le to include the headers that actually make up your solution. Also don’t forget to submit the accompanying .cc les.

Provided test harness: q2main.cc

No test suite required; submit your code on Due Date 2.

Please note that correctness marks awarded by Marmoset constitute only one part of your overall grade on this question. Your code will be carefully hand-marked to ensure that it is implemented correctly and properly designed. You must, therefore, make sure your code is very clearly readable. If the TA is unable to follow your solution, it will be assumed to be wrong.

  1. Rewrite your solution for Question 2, such that it uses std::unique_ptr instead of raw pointers. The example from Question 2, rephrased as follows, should work with your imple-mentation:

make_unique<Concatenation>( make_unique<Star>(

make_unique<Disjunction>( make_unique<Word>(“cat”), make_unique<Word>(“dog”)

)

),

make_unique<Word>(“bird”)

);

The les you submit will at least contain the le re.h. That is the le that our testing will include. You may use this le to include the headers that actually make up your solution. Also don’t forget to submit the accompanying .cc les.

Provided test harness: q3main.cc (do not submit)

No test suite required; submit your code on Due Date 2.

Please note that correctness marks awarded by Marmoset constitute only one part of your overall grade on this question. Your code will be carefully hand-marked to ensure that it is implemented correctly and properly designed. You must, therefore, make sure your code is very clearly readable. If the TA is unable to follow your solution, it will be assumed to be wrong.

  1. The last challenge in creating a general-purpose regular-expression matcher is parsing. Specif-ically, we wish to take a string s, containing a regular expression in human-readable format, and produce an equivalent RegExp object.

There are many parsing algorithms; one of the simplest is known as recursive descent. A recursive descent parser works by having one parsing function for each element of abstract syntax, i.e., for each kind of expression. Each of these functions consumes a string parameter and produces a parsed expression object:

std::unique_ptr<Item> parseItem(const string &s); // Whatever type Item happens to be

For this problem, we recommend having one such function for each of Disjunction, Concatenation, Star, and Word. Each such function would rst determine whether the string represents the kind of expression that the function is looking for. If so, then the function splits the string into two (or one, in the case of Star), and (mutually) recursively calls the appropriate recog-nition function for each part; it then creates the appropriate regular expression object with

the parsed parts as subobjects. If not, it calls the recognition function with the next lowest precedence, which will attempt to parse the string as that kind of expression.

For example, the parseDisjunction function should work roughly as follows:

    • determine if s contains a | operator, not nested inside parentheses;

if so, nd the rst such operator, and split the string into the part before the |, and the part after the |; parse the two pieces, and then build a Disjunction object from the

    • results;

if not, parse s as a concatenation (i.e., call parseConcatenation)

To facilitate testing of your parser, add a virtual print method to your RegExp class hierarchy. This virtual method should take an lvalue reference to an ostream as parameter, and return the same reference as its result. The sample executable will show you how the di erent kind of expressions should be printed. Also include the following overload of operator<< in your solution:

std::ostream &operator<<(std::ostream &out, RegExp &re) { return re.print(out);

}

We will provide a test harness, suitable for testing your code. After each command you issue to the test harness, it will print the parsed expression, using the method described above.

Note: In the interest of simplicity, you will treat each multi-character word as a concatenation of single-character words. So the regular expression dog will print as

Concatenation (d,Concatenation (o,g))

You will need to submit a test suite for your program, in a format compatible with runSuite.

The les you submit will at least contain the le re.h. That is the le that our testing will include. You may use this le to include the headers that actually make up your solution. Also don’t forget to submit the accompanying .cc les.

Provided test harness: q4main.cc (do not submit)

Submit your test suite on Due Date 1; submit your code on Due Date 2.

Please note that correctness marks awarded by Marmoset constitute only one part of your overall grade on this question. Your code will be carefully hand-marked to ensure that it is implemented correctly and properly designed. You must, therefore, make sure your code is very clearly readable. If the TA is unable to follow your solution, it will be assumed to be wrong.

  1. Now that you have a working regular expression recognizer, the next step is to look for a match for a regular expression within a string. Write the following function:

bool containsMatch(RegExp *re, const string &s);

It should answer true if re matches any substring of s. Do not worry if the check takes a quadratic number of attempts in the length of s. There are more e cient ways to solve this problem, but those are the realm of CS 241.

Once you have this working, determine how to add support for the special words ^ and $. In order to be compatible with our testing, these must be handled by creating two additional classes called Begin and End, whose constructors take no arguments. To simplify this process, you are permitted to assume that the input string is coded in 7-bit ASCII, and may use the characters with ASCII values 128 and 129 as indicating the beginning and end of the line, respectively:

bool containsMatch(RegExp *re, const string &s) { string s2 = ’\200’ + s + ’\201’;

// then proceed using s2

}

Once you have this working, add support for the dot (.) operator, via a class called Dot.

The les you submit will at least contain the le re.h. That is the le that our testing will include. You may use this le to include the headers that actually make up your solution. Also don’t forget to submit the accompanying .cc les.

Provided test harness: q5main.cc (do not submit)

Submit your test suite on Due Date 1; submit your code on Due Date 2.

Please note that correctness marks awarded by Marmoset constitute only one part of your overall grade on this question. Your code will be carefully hand-marked to ensure that it is implemented correctly and properly designed. You must, therefore, make sure your code is very clearly readable. If the TA is unable to follow your solution, it will be assumed to be wrong.

  1. Finally, complete your egrep program. For this problem, you are not required to support the command-line ags that were expected of you on A1. Your program should be invoked as follows:

my-egrep pattern file file …

It will print all lines in each file that contain a match to pattern. If no les are given, it takes its input from stdin.

The pattern will be a regular expression involving the operations you were asked to support. You should parse the regular expression using your solution from problem 4, and then proceed to print lines from the les that contain a match to the pattern.

If you have solved all of the problems before this one, this should be a straightforward exercise.

Provided test harness: none. Submit your complete program, including a Make-le that builds the target a3q6.

No test suite required; submit your code on Due Date 2.

Please note that correctness marks awarded by Marmoset constitute only one part of your overall grade on this question. Your code will be carefully hand-marked to ensure that it is implemented correctly and properly designed. You must, therefore, make sure your code is very clearly readable. If the TA is unable to follow your solution, it will be assumed to be wrong.

Assignment 3 (Solved)
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