Description
Write a .Rmd le to answer these questions, knitting it to .html along the way. Start by pasting this outline to help the grader nd your answers:
(Your Name Here)
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1 Pumpkins
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1a.
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1b.
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1c.
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1d.
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1e.
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1f.
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2. Penguins
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2a.
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2b.
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2c.
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2d.
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A pumpkin farmer weighed a simple random sample of size n = 20 pumpkins, with these results:
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9.6, 8.8, 5.1, 9.7, 9.1, 8.9, 8, 9.2, 2.7, 9.1, 8.5, 7.3, 9.3, 9.6, 4.1, 9.9, 7.6, 9, 7.2, 8.5
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Create a QQ plot of the weights. Do you think it is reasonable to assume that the population distribution is normal? Explain your answer.
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Regardless of your answer to (a), use R to perform the bootstrap with 2000 resamplings to create a 90% con dence interval for . (Show your R code and its output.)
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Suppose you want to know whether the true mean pumpkin weight for this pumpkin farmer’s patch is greater than 7.2. Conduct a bootstrap hypothesis test with 2000 resamplings at a signi cance level = 0:05.
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What is the p-value?
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What conclusion do you draw?
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Conduct a hypothesis test at level = 0:05 to see whether we can assert the data are strong evidence the true median weight for this pumpkin farmer’s patch is greater than 7.2.
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What is the value of the test statistic?
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What is the p-value?
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What is your conclusion?
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Most penguin species are not sexually dimorphic, which means they lack obvious outward body characteristics which indicate sex. Observation of behavior or a blood test can determine Penguin sex. A penguin researcher is interested in estimating the proportion of females in a large penguin population. She takes a random sample of n = 20 penguins and determines the sex of each one using a blood test. She nds 12 males and 8 females. Let be the proportion of females in the population.
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Find a point estimate of .
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Find the estimated standard deviation of your estimate.
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Is it reasonable to compute a 95% con dence interval for using the normal approximation in this case? If it is possible, explain why, and make the interval. If it is not reasonable, explain why.
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Are the data strong evidence the population proportion of females is di erent from 63%? Run a test at level = :05 to nd out.
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2